两个LazyForeach的List如何组合在一起，并且支持懒加载

@Entry 
@Component 
struct Combination { 
  @Builder 
  header() { 
    ... 
  } 
 
  builder() { 
    Column() { 
      Scroll() { 
        Column() {            
        ListA()            
        ListB()          
        } 
      } 
    } 
  } 
} 
 
@Component 
export struct ListA { 
  @Builder 
  FunBuilder() { 
  }; 
 
  @BuilderParam slot: () => void = this.FunBuilder; 
 
  build() { 
    Column() { 
      List() { 
        ListItem() { 
          this.slot(); 
        } 
 
        LazyForEach 
        ( 
           ... 
        ) 
      }.nestedScroll({ scrollForward: NestedScrollMode.SELF_FIRST, scrollBackward: NestedScrollMode.PARENT_FIRST }) 
    } 
  } 
 
  @Component export struct ListB {     
  build() { 
    Column() { 
      List() { 
        LazyForEach 
        ( 
           ... 
        ) 
      }.nestedScroll({ scrollForward: NestedScrollMode.PARENT_FIRST, scrollBackward: NestedScrollMode.SELF_FIRST }) 
    } 
  } 
}