如何通过判断函数入参类型实现不同代码逻辑

class Game{ 
  // ... 
} 
 
function Solve(message:number | string | boolean | Map<string, number> | Record<string, number> | Game){ 
  // Game：类型判断 
  if(message instanceof Game){ 
    console.info('Game') 
    return 
  } 
 
  let typeStr:string = message.constructor.toString().substring(9,12) 
  switch (typeStr){ 
    case 'Num':console.info('number');break; 
    case 'Str':console.info('string');break; 
    case 'Boo':console.info('boolean');break; 
    case 'Map':console.info('Map');break;  // Map：类型判断 
    case 'Obj':console.info('Record');break;  // Record：类型判断 
  } 
}