#鸿蒙学习大百科#如何监听窗口不可交互与可交互事件？

onWindowStageCreate(windowStage: window.WindowStage): void {
  try {
    windowStage.on('windowStageEvent', (data) => {
      console.info('Succeeded in enabling the listener for window stage event changes. Data: ' +
      JSON.stringify(data));

      // 根据事件状态类型选择进行相应的处理
      if (data == window.WindowStageEventType.SHOWN) {
        console.info('current window stage event is SHOWN');
        // 应用进入前台，默认为可交互状态
        // ...
      } else if (data == window.WindowStageEventType.HIDDEN) {
        console.info('current window stage event is HIDDEN');
        // 应用进入后台，默认为不可交互状态
        // ...
      } else if (data == window.WindowStageEventType.PAUSED) {
        console.info('current window stage event is PAUSED');
        // 前台应用进入多任务，转为不可交互状态
        // ...
      } else if (data == window.WindowStageEventType.RESUMED) {
        console.info('current window stage event is RESUMED');
        // 进入多任务后又继续返回前台时，恢复可交互状态
        // ...
      }

      // ...
    });
  } catch (exception) {
    console.error('Failed to enable the listener for window stage event changes. Cause:' +
    JSON.stringify(exception));
  }
  }