HarmonyOS TLSSocket的二进制转成字符串的转换方法

现有TLSSocket无法支持二进制，强制发送字符串，但是我们业务只能获取到二进制，因此需要使用二进制转换成字符串的方法，我们尝试了两种转换

let   byteArray: Uint8Array = new Uint8Array([0x82,0x00,0x00,0x82,0x34,0x3d,0x30,0x00,0x31,0x31,0x3d,0x35,0x30,0x39,0x00,0x35,0x3d,0x33,0x32,0x00,0x31,0x3d,0x31,0x30,0x34,0x00,0x36,0x39,0x3d,0x63,0x6c,0x69,0x65,0x6e,0x74,0x55,0x6e,0x69,0x71,0x75,0x65,0x3d,0x30,0x45,0x39,0x44,0x38,0x33,0x35,0x34,0x2d,0x41,0x37,0x36,0x38,0x2d,0x34,0x45,0x44,0x46,0x2d,0x39,0x46,0x42,0x39,0x2d,0x36,0x38,0x39,0x34,0x43,0x39,0x39,0x30,0x31,0x35,0x32,0x43,0x00,0x63,0x6c,0x69,0x65,0x6e,0x74,0x54,0x79,0x70,0x65,0x3d,0x49,0x70,0x68,0x00,0x63,0x6c,0x69,0x65,0x6e,0x74,0x56,0x65,0x72,0x73,0x69,0x6f,0x6e,0x3d,0x38,0x2e,0x33,0x33,0x2e,0x39,0x39,0x2e,0x31,0x00,0x6d,0x61,0x72,0x6b,0x69,0x64,0x3d,0x75,0x6e,0x6b,0x6e,0x6f,0x77,0x6e,0x00,0x00])

let bufferStr = buffer.from(byteArray.buffer).toString();


const decoder = util.TextDecoder.create();
let bufferStr2 = decoder.decodeWithStream(byteArray,{stream:true})

发现发送出去的字节均和初始bytearray内的字节不一致，请问应该怎么转换