用户如何在APP中直接跳转到settings开启位置？

function
 openPermissionsInSystemSettings(): void {
          let
 context = getContext(        this
) as common.UIAbilityContext;
          let
 wantInfo = {
    action: 'action.settings.app.info',
    parameters: {
      settingsParamBundleName: 'com.example.myapplication' // 打开指定应用的详情页面
    }
  }
  context.startAbility(wantInfo).then(() => {
    // ...
  }).catch((err) => {
    // ...
  })
}
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
13.
14.
15.
16.
17.
18.